2u^2-19u+42=0

Solution for 2u^2-19u+42=0 equation:

Simplifying
2u2 + -19u + 42 = 0

Reorder the terms:
42 + -19u + 2u2 = 0

Solving
42 + -19u + 2u2 = 0

Solving for variable 'u'.

Factor a trinomial.
(7 + -2u)(6 + -1u) = 0

Subproblem 1
Set the factor '(7 + -2u)' equal to zero and attempt to solve:

Simplifying
7 + -2u = 0

Solving
7 + -2u = 0

Move all terms containing u to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -7 + -2u = 0 + -7

Combine like terms: 7 + -7 = 0
0 + -2u = 0 + -7
-2u = 0 + -7

Combine like terms: 0 + -7 = -7
-2u = -7

Divide each side by '-2'.
u = 3.5

Simplifying
u = 3.5
Subproblem 2
Set the factor '(6 + -1u)' equal to zero and attempt to solve:

Simplifying
6 + -1u = 0

Solving
6 + -1u = 0

Move all terms containing u to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + -1u = 0 + -6

Combine like terms: 6 + -6 = 0
0 + -1u = 0 + -6
-1u = 0 + -6

Combine like terms: 0 + -6 = -6
-1u = -6

Divide each side by '-1'.
u = 6

Simplifying
u = 6
Solution
u = {3.5, 6}